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Graph axes and labels E / V(SHE) pH solid qudrialtereals <Zn2+ < Zn2+ Zn2+ Zn Zn(OH)2 Zn(OH)2 Zn(OH)2 HZnO2- HZnO2- HZnO2- ZnO22- ZnO22- ZnO22- Lines Layer 4
 
Zn2+
Zn(OH)2
HZnO2−
ZnO22−
\[E_{e}=E^{0}-\frac{RT}{zF}ln\frac{[reduced]}{[oxidised]} \]\[ E_{e}=1.223-\frac{8.31 \times 298}{4\times 96500}ln\frac{[H_{2}O]}{[H^{+}]^4 p_{O{_{2}}}} \]\[ E_{e}=1.223-\frac{8.31 \times 298\times2.303 \times4}{4\times 96500}\text{log}\frac{1}{[H^{+}]} \] \[ E_{e}=1.223-0.0591\text{log}\frac{1}{[H^{+}]} \] \[ E_{e}=1.223-0.0591\enspace \text{pH} \]
\[ E_{e}=E^{0}-\frac{RT}{zF}ln\frac{[reduced]}{[oxidised]} \]\[ E_{e}=0-\frac{8.31 \times 298}{4\times 96500}ln\frac{p_{H{_{2}}}}{[H^{+}]^2 } \] \[ E_{e}=0-\frac{8.31 \times 298\times2.303 \times 2}{2 \times 96500}\text{log}\frac{1}{[H^{+}]} \] \[ E_{e}=-0.0591\text{log}\frac{1}{[H^{+}]} \] \[ E_{e}=-0.0591 \text{pH} \]
\[ E_{e}=E^{0}-\frac{RT}{zF}ln\frac{[Zn]}{[Zn^{2+}]} \] \[ E_{e}=-0.763+0.0295 \text{log}[Zn^{2+}] \textcolor{red}{^{*}} \] \[ E_{e}=-0.763+0.0295 \text{log}[10^{-6}] \] \[ E_{e}=-0.940 \textcolor{red}{^{**}} \]
\[ E_{e}=E^{0}-\frac{RT}{zF}ln\frac{[Zn][H_{2}O]^{2}}{[Zn(OH)_{2}][H^{+}]^{2}]} \] \[ E_{e}=-0.439-0.0591 \text{log}\frac{1}{[H^{+}]} \] \[ E_{e}=-0.439-0.0591 \text{pH} \]
\[ E_{e}=E^{0}-\frac{RT}{zF}ln\frac{[Zn][H_{2}O]^{3}}{[HZnO_{2}^-][H^{+}]^{3}} \] \[ E_{e}= 0.054 - 0.0886 \text{log}\frac{1}{[H^{+}]}+0.0295 \text{log}[HZnO_{2}^{-}]\textcolor{red}{^{*}} \] \[ E_{e}=-0.124 - 0.0886 \text{pH} \]
\[ E_{e}=E^{0}-\frac{RT}{zF}ln\frac{[Zn][H_{2}O]^{2}}{[ZnO_{2}^{2-}][H^{+}]^{4}} \] \[ E_{e}=0.441 - 0.1182 \text{log}\frac{1}{[H^{+}]}+0.0295 \text{log}[ZnO_{2}^{2-}]\textcolor{red}{^{*}} \] \[ E_{e}=0.264 - 0.1182 \text{pH} \]
\[ K=exp\frac{-\Delta G^0}{kT} \] \[ K = 9.03 \times 10^{10} \]\[ \text{In addition: } K = \frac{[Zn^{2+}]}{[H^+]^2} \] \[ \text{log} K = \text{log}[Zn^{2+}]\textcolor{red}{^{*}} +2 \text{pH} \] \[ \text{pH} = 8.45 \textcolor{red}{^{**}} \]
\[ K=exp\frac{-\Delta G^0}{kT} \] \[ K = 2.15 \times 10^{-17} \] \[ \text{In addition: }K = [HZnO_{2}^-][H^+] \] \[ \text{log} K = \text{log}[HZnO_{2}^-]\textcolor{red}{^{*}} - \text{pH} \] \[ \text{pH} = 10.7 \textcolor{red}{^{**}} \]
\[ K=exp\frac{-\Delta G^0}{kT} \] \[ K = 7.83 \times 10^{-15} \] \[ \text{In addition: }K = \frac{[ZnO_2^{2-}][H^+]}{[HZnO_{2}^-]} \] \[ \text{log} K = \text{log}[ZnO_{2}^{2-}]\textcolor{red}{^{*}} - \text{pH} - \text{log}[HZnO_{2}^-] \textcolor{red}{^{*}} \] \[ \text{pH} = 13.1 \textcolor{red}{^{**}} \]