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When a ray parallel to the optic axis (normal to the plane
of the lens) is incident on the lens, it is bent so that it crosses
the optic axis at the focal point of the lens. In fact, this defines
the focussing power of the lens.
A feature of the lens is that the direction the lens is
travelling in makes no difference. We therefore see that any ray originating
from the focal point of the lens is bent so that it leaves travelling
parallel to the optic axis.
Consistent with these rules is that any ray travelling
through the centre of the lens is not affected.
To see how the lens magnifies an object, three rays are
drawn from the point on the object furthest from the optic axis.
The image appears in focus where the rays meet on the opposite side
of the lens.
The relationship between the focal length, f,
of the lens and the distance, v, at which the image of a point
source at distance u in front of the lens is in focus is given
by the thin lens equation as follows:
1/u + 1/v = 1/f
The resulting image will be at a magnification of M,
where
M = u/v
We shall explore the behaviour of a lens according to
the above equations in the following simulation.
We see that the magnification of the object is dependent
on its position relative to the focal point of the lens. Use the slider
to move the object relative to the lens.
When is the magnification greatest? What would you have predicted from
the lens equation?
Alternatively we can alter the strength of the lens - this moves the
focal point of the lens
.In the electron microscope we may easily change the strengths of the
lens by altering the amount of current flowing through the coils.