• Notched bar in tension
The plane strain condition is satisfied when breath, b » h, the depth of the bar.
Lower-Bound:
Find a stress system, e.g. σ = 0 in the length of the bar where there is the notch, σ = 2k elsewhere.
Therefore, for a breadth b, P = 2khb = load = stress × area
Upper-Bound:
Postulate a suitable simple deformation pattern.
Assume yielding by slip on 45º shear planes with shear yield stress k. Let displacement along shear plane AB = δx.
Then internal work done = \( {k.\left| {AB} \right|b\delta x} = k\sqrt 2 bh\delta x\), where the force is \( k\left| {AB} \right|b \) acting on the shear plane AB.
Distance moved by the external load \(P = \delta x\cos {45^ \circ }\) = \(\frac{{\delta x}}{{\sqrt 2 }}\)
\( \Rightarrow P \) \(\frac{{\delta x}}{{\sqrt 2 }}\) = \(k\sqrt 2 bh\delta x\)
\( \Rightarrow P = 2kbh\)
So, here we obtain the same result for the upper bound and lower bound \( \Rightarrow P = 2kbh\) is the true failure load, the load required to cause plastic flow.